45x^2+450x-4500=0

Solution for 45x^2+450x-4500=0 equation:

45x^2+450x-4500=0

a = 45; b = 450; c = -4500;
Δ = b2-4ac
Δ = 4502-4·45·(-4500)
Δ = 1012500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1012500}=\sqrt{202500*5}=\sqrt{202500}*\sqrt{5}=450\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(450)-450\sqrt{5}}{2*45}=\frac{-450-450\sqrt{5}}{90}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(450)+450\sqrt{5}}{2*45}=\frac{-450+450\sqrt{5}}{90}
$